How to find the eigenfunctions of a differential operator.
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To find its eigenfunction $f$, it is equivalent to solve $Lf=\lambda f$, that is, $$\frac{d^2f}{dx^2}=\lambda f.$$ This is an second order ODE with constant coefficient, which can be solved. After finding all the possible solutions for $f$, we can consider the normalized condition and initial conditions to find the specify $f$.
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ODP
Updated on August 01, 2022Comments

ODP 3 months
Consider a linear differential operator $$L=\frac{d^2}{dx^2}.$$ How would one determine that the normalised eigenfunctions of $L$ are $$\phi_n(x)=\sqrt{2}\sin{(n\pi x)}?$$

tired over 6 yearswhich initial conditions do u have in mind?

ODP over 6 yearsI think y(1)=Cy(0) but I will doublecheck and get back to you later.


ODP over 6 yearsOK cool, so with boundary conditions $f(0)=0$ and $f(\frac{\pi}{4})=1$ I obtain $f=A\cos{\lambda x}+B\sin{\lambda x}=\sqrt{2}\sin{\lambda x}$ where $A=0$ and $B=\sqrt{2}$ from the boundary conditions. But then how does one determine that $\lambda_n=n\pi$?