# How does grounding work?

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## Solution 1

It will normally just reach the negative terminal. Generally, current only flows in closed circuits. Hence, it could only flow into the ground if the positive terminal was also connected to ground, for example if you touch the positive terminal and you stand on the ground with bare feet or so.

Then you might ask, what the purpose of grounding is. The absolute level of voltage (the reference potential) is not well-determined if you do not ground the circuit. Only potential differences ("voltages") are defined. So anything that your circuit "catches" from the environment, would serve as the potential reference, because the whole circuit acts as a capacitor and an inductor relative to the environment. This is undesirable if different circuits are connected together (for example your computer and your stereo), because their different reference potentials will then cause additional currents, which might interfere with the function of the devices.

Another reason for grounding is safety. For voltages dangerous to humans (usually above ~50 Volts for AC), grounding ensures that a defective device does not expose its mains voltage to touchable parts. If you ground the housing of a device, any accidental internal contact between the housing and mains voltage will cause very high currents (ground is assumed to be low impedance), the fuses or circuit breakers to be triggered immediately, and consequentially, the current to be stopped long before you happen to touch the housing of the device and meet your maker prematurely.

Yet another application for grounding is that you only need a single wire to close circuits. In a car for example, a headlight only has one wire (per lamp), the circuit to the battery is closed via the car's chassis. However, this is not "grounding" in the literal sense, because the car's chassis is not properly connected to the earth (the tires have a high resistance). So this is more like a kind of logical grounding, which is also used internally in most electronic circuit boards: supplying the negative battery voltage by a bulk conductor to everywhere around the components.

## Solution 2

Theoretically, none of the electricity will flow to ground because the current into the battery must equal the current out and there is no way that the circuit as a whole can gain or lose electrons other than through that single connection to ground. This is assuming our analysis of the circuit begins in a steady state with node A already at the same potential as ground: there is no reason for electrons to flow either way because the two nodes (ground and node A) are at the same potential to begin with, while the electrochemical reaction in the battery requires just as many electrons to enter the anode as are released onto the cathode.

But it is informative to take a brief excursion towards reality in order to illustrate a point. In reality, electrons will flow to ground in order to equalise the potential between ground and node A. Even assuming that node A starts with the same voltage as ground, imagine electrons being radiated onto the circuit from an external source. Without the connection to ground, the circuit as a whole would build up a negative static charge. It would continue to operate as normal, just with node A at -1000V and the anode of the battery at, say, -997V. With the ground connection in place, such a potential would immediately cause electrons to flow and equalise the potential back to 0V and 3V with respect to ground. Small scale "common mode" deviations from ground could even occur momentarily as a result of the internal dynamics of the battery: imagine turbulence in the electrolyte temporarily holding a bunch of negative ions away from the cathode, for example.

It is possible to model this concept within the familiar electrical engineering abstraction of ideal resistors, batteries etc.. Any static charge on the circuit can be thought of as existing across a capacitance to ground. The discharge of that static charge would theoretically take 0 time, but that can be changed by adding a resistance between node A and ground.

Above: with no grounding, the two nodes of the circuit acquire a 1000V and 997V potential with respect to ground. This can be removed again by discharging the capacitor.

With this amended model, the circuit can acquire an overall charge via the switch on the left hand side, which represents the extrinsic electron beam described earlier. At a later point, the circuit can then discharge to ground through the resistor on the right resulting in a flow of current. But for most engineering purposes, it is convenient to think of this happening continuously and instantly, with node A always at 0V with respect to ground and no current flowing in or out (no random imaginary CRT monitors spraying electrons onto our circuits and grounds alike; no unwanted resistance to ground either), so we set the capacitance to zero and the discharge resistance to zero.

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### user545735

Updated on August 01, 2022

• user545735 over 1 year

This is a simple circuit that has been grounded. My question is, after reaching point $$A$$ will the current $$I$$ reach the negative terminal of the battery or will it go to the earth?

• my2cts over 2 years
It is all the same.
"If you ground the housing of a device," don't you mean if you not ground the housing?
• oliver over 2 years
@Barbierium: I am not sure why you think that. If the housing is grounded/earthed (desired) a contact between mains and the housing (undesired, dangerous) immediately causes a short circuit (desired), which blows the circuit breaker, and thus prevents that mains voltage stays at the housing and anyone touches it.
My fault! I thought damage was done to the useful circuit. But it's the fuse that is damaged, preventing damage to the useful circuits.
• oliver over 2 years
It's human fatality that is prevented by protective earthing. If you touch an electric heater with a metal housing, you don't expect to be killed. You don't care so much about the fuse (or circuit breaker, which can easily be reenacted anyway). And, you don't care about the heater, because it is already damaged anyway (probably a broken cable that got in touch with the housing).
So when the heater is already broke, this will cause electricity to be on the housing? Or maybe another cause. And this accumulated charge is taken away by the Earth (instead of by you or me upon touching the house)?
• oliver over 2 years
If electricity is on the housing, that is certainly not a mode of normal function, because it is potentially deadly. So the device would be called broken, yes. The saftey is not mainly restored by shorting the failure current to ground, although this would already help somehow because the resistance to ground would be a lot lower than the path through your body (the current tendentially takes the path of least resistance). The safety is rather restored by the circuit breaker detecting the resulting overcurrent and interrupting the circuit.
• Ján Lalinský over 2 years
> Generally, current only flows in closed circuits. -- This is unfortunate formulation. Generally, it does flow also in closed circuits. However, only AC current can do so in a sustained way (because of its oscillating direction). DC current can flow in a closed circuit for only a limited time, which is often extremely short due to low capacitance of the disconnected circuit.
• Sebastian Riese over 2 years
Note: For modern installations the metallic housing is connected to a special protective ground. (While there are a ground and a phase wire that are used to transfer the current). The protective ground branches off the "main" ground at the entry to the building, and is used to have a ground wire that is not counted by residual-current device. This leads to a far more sensitive circuit breaking (typically breaking the circuit at 30mA residual current) than having a fuse blow (which typically requires 16 A for 230V home installations). Of course, the details vary by country.
• Peter Cordes over 2 years
@oliver: Related Q&A on diy.stackexchange today: I live in an older home without ground wiring. Is it safe to install 3-prong GFCI with only a hot and neutral? - some of the answers there discuss the relative merits of GFCI protection vs. grounding, and corner cases where one will save you but the other won't.
• Buraian over 2 years
" because the whole circuit acts as a capacitor and an inductor relative to the environment. " it would be worth to elaborate on this
• oliver over 2 years
@JánLalinský: Absolutely true. I wanted to keep it simple, which is what I tried to indicate by "generally".
• oliver over 2 years
@SebastianRiese: very good comment. I considered mentioning RCD's, but I thought it was a little off-question.
• oliver over 2 years
@Buraian: I agree that this is an interesting point. However, I think that it is off-question. I have tried to find a link to a respective SE-question, but didn't find any. Although it is rather trivial that a circuit is a capacitor and an inductor (all conductors are), feel free to ask another question, that others may find more sophisticated answers to.
• nanoman over 2 years
@JánLalinský I assume you meant: "Generally, it does flow also in open circuits... DC current can flow in an open circuit for only a limited time".
• Ján Lalinský over 2 years
@nanoman yes! It should be open circuit.
• oliver over 2 years
@nanoman: Haha, Jan miswrote it and I misread it, but in the end my answer to Jan's Comment referred to what he meant... Minus times minus is plus. ;-)
• Sebastian Riese over 2 years
@oliver Yes, there was no need for it in the answer – I just wanted to mention it, given the direction the discussion in the comments took.