Ph · Physics

How to Measure the EMF of a Cell

Published By the 9to5Science editorial team

At a glance

  1. 1. Choose a method

    Use a high-input-resistance voltmeter for a quick estimate, or a potentiometer for a near-zero-current measurement.

  2. 2. Connect across terminals

    Connect the measuring instrument in parallel with the cell, observing polarity and avoiding a short circuit.

  3. 3. Read or balance

    A voltmeter reads terminal voltage; a potentiometer finds the voltage at which no current flows from the test cell.

  4. 4. Interpret the result

    Treat the open-circuit or null-balance reading as the cell’s EMF; a loaded cell’s terminal voltage can differ.

A cell’s electromotive force (EMF) is the energy it supplies per unit charge. Despite the word “force,” EMF is a voltage, measured in volts. To measure it, you can use a voltmeter for a quick reading or a potentiometer for a null-balance measurement that draws essentially no current from the cell.

The distinction matters because a cell’s voltage at its terminals can change when it supplies current. A loaded-cell reading is not always the cell’s EMF.

Quick method: use a voltmeter

Set a digital multimeter to measure DC voltage, select a range above the cell’s expected voltage, and connect the meter in parallel across the cell: red lead to the positive terminal and black lead to the negative terminal. Read the displayed voltage. Do not connect the meter in current mode across the terminals; that can create a short circuit.

A voltmeter has finite input resistance, so it draws a small current. If the cell has EMF E\mathcal{E} and internal resistance rr, a simple model for a discharging cell gives its terminal voltage as

V=E−Ir,V = \mathcal{E} - Ir,

where II is the current supplied. With the meter connected, the meter itself is the load. If its resistance is RVR_V, the model gives

V=ERVr+RV.V = \mathcal{E}\frac{R_V}{r+R_V}.

When RVR_V is much larger than rr, the meter draws very little current and VV is close to E\mathcal{E}. For many ordinary measurements, this is accurate enough. The exact input resistance depends on the meter and its range.

More accurate method: use a potentiometer

A potentiometer can measure EMF without drawing current from the cell being tested at the balance point. It uses a uniform resistance wire carrying a steady current from a separate power supply. Because the wire is uniform, the potential drop along it is proportional to its length.

A typical arrangement works as follows:

  1. Connect the ends of a uniform wire to a separate driver supply, usually with a rheostat to adjust the current. This establishes a steady potential gradient along the wire.
  2. Connect the positive terminal of the test cell to the wire’s high-potential end. Connect the cell’s negative terminal to a galvanometer and a movable contact, called a jockey.
  3. Slide the jockey along the wire until the galvanometer reads zero. At this null point, no current flows from the test cell through the measuring circuit.
  4. Measure the length ll from the high-potential end to the balance point. If the potential drop per unit length is kk, then
E=kl.\mathcal{E} = kl.

To find kk, first balance a reference cell with known EMF Eref\mathcal{E}_{\mathrm{ref}} at length lrefl_{\mathrm{ref}}. Then k=Eref/lrefk=\mathcal{E}_{\mathrm{ref}}/l_{\mathrm{ref}}. Keep the driver supply and wire current unchanged when measuring the unknown cell.

Worked example

A 1.50 V1.50\,\text{V} reference cell balances at 75.0 cm75.0\,\text{cm}. The potential gradient is

k=1.50 V75.0 cm=0.0200 V/cm.k=\frac{1.50\,\text{V}}{75.0\,\text{cm}}=0.0200\,\text{V/cm}.

An unknown cell balances at 62.5 cm62.5\,\text{cm} with the same wire current. Its EMF is

E=(0.0200 V/cm)(62.5 cm)=1.25 V.\mathcal{E}=(0.0200\,\text{V/cm})(62.5\,\text{cm})=1.25\,\text{V}.

Alternatively, using the two balance lengths directly gives Ex=Eref(lx/lref)=1.25 V\mathcal{E}_{x}=\mathcal{E}_{\mathrm{ref}}(l_x/l_{\mathrm{ref}})=1.25\,\text{V}.

Common mistakes

  • Measuring in current mode: A current meter has very low resistance. Connecting it directly across a cell can cause a large current and damage the meter or cell. Use voltage mode for a direct terminal measurement.
  • Calling every terminal reading the EMF: Under load, the terminal voltage differs from the EMF because of internal resistance. Reduce the load current or use a potentiometer if the distinction matters.
  • Reversing the leads: Reversed leads produce a negative reading on many digital meters. Swap the leads or interpret the sign according to the chosen polarity.
  • Changing the potentiometer current: The potential gradient changes with wire current. Recalibrate or keep the current fixed when comparing balance lengths.
  • Letting the wire heat up: Excessive current can heat the wire, changing its resistance and spoiling the assumption of a stable, uniform potential gradient. Use a modest current and take readings promptly.

For a quick check of a battery, a suitable digital voltmeter is usually sufficient. For a laboratory measurement where loading error must be minimized, the potentiometer’s null method is the better choice.

References

  1. OpenStax, University Physics Volume 2, Section 10.2: Electromotive Force
  2. Halliday, Resnick, and Walker, Fundamentals of Physics

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