Proof of $(A+B) \times (AB) = 2(A X B)$
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Using the distributive law, $$(A+B)\times(AB)=A\times AA\times B+B\times AB\times B$$ $$A\times A=B\times B=0$$ $$(A+B)\times(AB)=0A\times B+B\times A0$$ $$B\times A=A\times B$$ $$(A+B)\times(AB)=A\times BA\times B=2(A\times B)$$
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Shrish Shankar about 2 months
Proof of $(A+B) \times (AB) = 2(A \times B)$, where 'A' and 'B' are vectors

MPW over 6 yearsWhat about said proof?
