Ma · Mathematics

How to Expand the Lower Incomplete Gamma Function for s < 0

Published By the 9to5Science editorial team

At a glance

  1. 1. Check the parameter

    The expansion applies when s is negative but not an integer; at nonpositive integers the function has poles.

  2. 2. Use the power series

    Expand the exponential and continue the resulting series in s.

  3. 3. Substitute values

    For positive x, use x to the power s and sum terms with denominators s+n.

  4. 4. Interpret the result

    For s < 0 this is analytic continuation, not the original integral from zero.

For positive xx, the lower incomplete gamma function has a useful power series even when s<0s<0. The main caveat is that its usual integral definition no longer converges at zero. The series instead gives the function by analytic continuation in the parameter ss.

For negative noninteger ss, the expansion is

γ(s,x)=xs∑n=0∞(−x)nn!(s+n).\gamma(s,x)=x^s\sum_{n=0}^{\infty}\frac{(-x)^n}{n!(s+n)}.

It converges for every finite positive xx. The excluded values s=0,−1,−2,…s=0,-1,-2,\ldots are poles of γ(s,x)\gamma(s,x) as a function of ss.

Why the integral needs continuation

When Re⁡(s)>0\operatorname{Re}(s)>0, the lower incomplete gamma function is defined by

γ(s,x)=∫0xts−1e−t dt.\gamma(s,x)=\int_0^x t^{s-1}e^{-t}\,dt.

Near t=0t=0, the exponential approaches 11, so the integrand behaves like ts−1t^{s-1}. The integral converges at zero only when Re⁡(s)>0\operatorname{Re}(s)>0. For real s<0s<0, inserting that value directly into the integral gives a divergent improper integral; it does not define γ(s,x)\gamma(s,x) there.

The gamma function itself, and the incomplete gamma functions, can be extended meromorphically in ss. The series below is one way to express that extension. For real positive xx, there is no branch choice involved in xsx^s. For complex xx, a branch of xsx^s must be specified, commonly the principal branch.

Deriving the series

Start in the region where the integral converges and expand the exponential:

e−t=∑n=0∞(−t)nn!.e^{-t}=\sum_{n=0}^{\infty}\frac{(-t)^n}{n!}.

Termwise integration gives

γ(s,x)=∫0xts−1∑n=0∞(−t)nn! dt=∑n=0∞(−1)nn!xs+ns+n=xs∑n=0∞(−x)nn!(s+n).\begin{aligned} \gamma(s,x) &=\int_0^x t^{s-1}\sum_{n=0}^{\infty}\frac{(-t)^n}{n!}\,dt\\ &=\sum_{n=0}^{\infty}\frac{(-1)^n}{n!}\frac{x^{s+n}}{s+n}\\ &=x^s\sum_{n=0}^{\infty}\frac{(-x)^n}{n!(s+n)}. \end{aligned}

This derivation is initially valid for Re⁡(s)>0\operatorname{Re}(s)>0. The right-hand side is a meromorphic function of ss, with possible poles where a denominator s+ns+n vanishes. It therefore supplies the analytic continuation to negative noninteger values of ss. For fixed such ss, the factorial in the denominator ensures convergence for every finite xx.

Worked example: s=−12s=-\tfrac12

Set s=−12s=-\tfrac12. The series becomes

γ ⁣(−12,x)=x−1/2(−2−2x+x23−x315+x484−⋯ ).\gamma\!\left(-\frac12,x\right) =x^{-1/2}\left( -2-2x+\frac{x^2}{3}-\frac{x^3}{15}+\frac{x^4}{84}-\cdots \right).

For example, at x=14x=\tfrac14 this gives the convergent representation

γ ⁣(−12,14)=2(−2−12+148−1960+121504−⋯ ).\gamma\!\left(-\frac12,\frac14\right) =2\left( -2-\frac12+\frac{1}{48}-\frac{1}{960}+\frac{1}{21504}-\cdots \right).

Each coefficient comes directly from 1/[n!(n−12)]1/[n!(n-\tfrac12)], with the alternating factor (−x)n(-x)^n. The leading behavior as x→0+x\to0^+ is −2x−1/2-2x^{-1/2}; the function is not finite at zero for this negative parameter.

Recurrence as another way to evaluate it

The recurrence

γ(s+1,x)=sγ(s,x)−xse−x\gamma(s+1,x)=s\gamma(s,x)-x^s e^{-x}

can relate a negative noninteger parameter to one with a larger real part. Solving for the desired value gives

γ(s,x)=γ(s+1,x)+xse−xs,s≠0.\gamma(s,x)=\frac{\gamma(s+1,x)+x^s e^{-x}}{s},\qquad s\ne0.

For instance, this expresses γ(−12,x)\gamma(-\tfrac12,x) in terms of γ(12,x)\gamma(\tfrac12,x) and an elementary term. The recurrence is useful for computation, but it does not remove the poles at nonpositive integer ss.

For large positive xx and noninteger ss, another representation is γ(s,x)=Γ(s)−Γ(s,x)\gamma(s,x)=\Gamma(s)-\Gamma(s,x). The upper incomplete gamma function Γ(s,x)\Gamma(s,x) decays exponentially as xx grows, so γ(s,x)\gamma(s,x) approaches Γ(s)\Gamma(s). This large-xx behavior is distinct from the power series, which is often most convenient for moderate or small xx.

Common mistakes

  • Using the integral for s<0s<0. Its divergence at zero means the integral cannot be used as an ordinary improper integral in that range.
  • Using the series at a pole. If s=−ms=-m for a nonnegative integer mm, the term with n=mn=m has denominator zero. The meromorphic function has a pole there; the displayed formula does not give a finite value.
  • Calling the series an asymptotic expansion. For fixed admissible ss and finite xx, it is a convergent power series (with the prefactor xsx^s), not merely a large- or small-xx approximation.
  • Ignoring the parameter convention. Some contexts discuss a finite part or a regularized value at a pole. That requires an additional convention and is not the ordinary meromorphic value of γ(s,x)\gamma(s,x).

References

  1. NIST Digital Library of Mathematical Functions, Chapter 8: Incomplete Gamma and Related Functions

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