Ma · Mathematics

How Differential Forms Restrict to Submanifolds

Published By the 9to5Science editorial team

At a glance

  1. 1. Include the submanifold

    Represent the submanifold with a smooth inclusion map into the ambient manifold.

  2. 2. Pull back the form

    Apply the inclusion’s pullback to obtain a differential form on the submanifold.

  3. 3. Evaluate tangent vectors

    Feed the restricted form tangent vectors lying in the submanifold.

  4. 4. Check the degree

    A form of degree greater than the submanifold dimension pulls back to zero.

A differential form defined on a manifold MM can be used on a smooth submanifold S⊆MS\subseteq M, but the correct operation is not usually a pointwise set-theoretic restriction. The standard construction is the pullback along the inclusion of SS into MM.

If

i:S↪Mi:S\hookrightarrow M

is the inclusion map and ω\omega is a differential kk-form on MM, then the induced form on SS is

i∗ω.i^*\omega.

This is a kk-form on SS. It takes kk tangent vectors to SS, regards them as tangent vectors to MM, and evaluates ω\omega on them.

The definition through tangent vectors

At a point p∈Sp\in S, the tangent space TpST_pS is naturally a subspace of TpMT_pM. For v1,…,vk∈TpSv_1,\ldots,v_k\in T_pS, define

(i∗ω)p(v1,…,vk)=ωp(v1,…,vk).(i^*\omega)_p(v_1,\ldots,v_k)=\omega_p(v_1,\ldots,v_k).

The right-hand side makes sense because each vector tangent to SS is also tangent to MM.

More generally, if F:S→MF:S\to M is any smooth map, not necessarily an inclusion, then

(F∗ω)p(v1,…,vk)=ωF(p)(dFp(v1),…,dFp(vk)).(F^*\omega)_p(v_1,\ldots,v_k) =\omega_{F(p)}\bigl(dF_p(v_1),\ldots,dF_p(v_k)\bigr).

Restriction to a submanifold is the special case F=iF=i.

For a smooth function ff on MM, this gives

i∗f=f∣S,i^*f=f|_S,

the ordinary restriction of ff. For one-forms, however, the derivative directions must also be restricted to tangent directions of SS.

Coordinate formula

Suppose SS is parametrized by a smooth map

ϕ:U⊆Rr→M,\phi:U\subseteq\mathbb{R}^r\to M,

whose image lies in SS. To calculate the form on SS, pull it back by ϕ\phi.

For example, if ω\omega is a one-form in coordinates (x1,…,xn)(x^1,\ldots,x^n),

ω=∑j=1naj(x) dxj,\omega=\sum_{j=1}^n a_j(x)\,dx^j,

and the parametrization is

ϕ(u1,…,ur)=(x1(u),…,xn(u)),\phi(u^1,\ldots,u^r)=\bigl(x^1(u),\ldots,x^n(u)\bigr),

then

ϕ∗ω=∑j=1naj(ϕ(u)) d(xj∘ϕ)=∑j=1naj(ϕ(u))∑ℓ=1r∂xj∂uℓ duℓ.\phi^*\omega =\sum_{j=1}^n a_j(\phi(u))\,d(x^j\circ\phi) =\sum_{j=1}^n a_j(\phi(u))\sum_{\ell=1}^r \frac{\partial x^j}{\partial u^\ell}\,du^\ell.

Thus the ambient differentials dxjdx^j are replaced by their expressions along the parametrization.

For wedge products, pullback preserves multiplication:

ϕ∗(α∧β)=ϕ∗α∧ϕ∗β.\phi^*(\alpha\wedge\beta)=\phi^*\alpha\wedge\phi^*\beta.

It also commutes with exterior differentiation:

d(ϕ∗ω)=ϕ∗(dω).d(\phi^*\omega)=\phi^*(d\omega).

These identities are especially useful when working with differential forms on surfaces and curves.

Worked example: a plane in three-dimensional space

Let S⊆R3S\subseteq\mathbb{R}^3 be the plane z=0z=0. Its inclusion can be written as

ϕ(u,v)=(u,v,0).\phi(u,v)=(u,v,0).

Consider the ambient one-form

ω=x dy+z dx+y dz.\omega=x\,dy+z\,dx+y\,dz.

Using x=ux=u, y=vy=v, z=0z=0, and

dx=du,dy=dv,dz=0dx=du,\qquad dy=dv,\qquad dz=0

on the plane, we obtain

ϕ∗ω=u dv.\phi^*\omega=u\,dv.

Therefore the form induced on SS is u dvu\,dv, after identifying the plane with the (u,v)(u,v)-plane.

Now consider the two-form

η=dx∧dy+dy∧dz.\eta=dx\wedge dy+dy\wedge dz.

Its restriction is

ϕ∗η=du∧dv+dv∧0=du∧dv.\phi^*\eta=du\wedge dv+dv\wedge 0=du\wedge dv.

The term dy∧dzdy\wedge dz disappears because the zz-coordinate is constant along the plane.

A three-form on R3\mathbb{R}^3, such as

τ=dx∧dy∧dz,\tau=dx\wedge dy\wedge dz,

restricts to zero on the two-dimensional plane. There are only two independent tangent directions available, so three tangent vectors in TpST_pS must be linearly dependent. Consequently,

ϕ∗τ=du∧dv∧0=0.\phi^*\tau=du\wedge dv\wedge 0=0.

Worked example: the sphere

Let S2⊆R3S^2\subseteq\mathbb{R}^3 be the unit sphere, and consider the one-form

ω=x dy−y dx.\omega=x\,dy-y\,dx.

Using spherical coordinates away from the poles,

ϕ(θ,φ)=(sin⁡θcos⁡φ,sin⁡θsin⁡φ,cos⁡θ),\phi(\theta,\varphi) =(\sin\theta\cos\varphi,\sin\theta\sin\varphi,\cos\theta),

we have

ϕ∗ω=x dy−y dx.\phi^*\omega=x\,d y-y\,d x.

The coordinate differentials are

dx=cos⁡θcos⁡φ dθ−sin⁡θsin⁡φ dφ, dx=\cos\theta\cos\varphi\,d\theta-\sin\theta\sin\varphi\,d\varphi, dy=cos⁡θsin⁡φ dθ+sin⁡θcos⁡φ dφ. dy=\cos\theta\sin\varphi\,d\theta+\sin\theta\cos\varphi\,d\varphi.

Substitution gives

ϕ∗ω=(sin⁡θcos⁡φ) dy−(sin⁡θsin⁡φ) dx=sin⁡2θ dφ.\begin{aligned} \phi^*\omega &=(\sin\theta\cos\varphi)\,dy -(\sin\theta\sin\varphi)\,dx\\ &=\sin^2\theta\,d\varphi. \end{aligned}

Thus the ambient form x dy−y dxx\,dy-y\,dx becomes sin⁡2θ dφ\sin^2\theta\,d\varphi on the sphere.

The same method works for a surface given implicitly by an equation such as g(x,y,z)=0g(x,y,z)=0. In that case, one may either choose a local parametrization or evaluate the ambient form directly on tangent vectors satisfying

dgp(v)=0. dg_p(v)=0.

Indeed, the tangent space to a regular level surface is

TpS=ker⁡(dgp).T_pS=\ker(dg_p).

Differential forms that vanish on a submanifold

A form ω\omega restricts to zero on SS precisely when

ωp(v1,…,vk)=0\omega_p(v_1,\ldots,v_k)=0

for every p∈Sp\in S and every v1,…,vk∈TpSv_1,\ldots,v_k\in T_pS.

For a one-form, this means that ωp\omega_p annihilates all tangent vectors to SS. If SS is the level set g=0g=0 of a regular function, then every one-form of the form

ω=h dg\omega=h\,dg

restricts to zero on SS, because dg(v)=0dg(v)=0 for every v∈TSv\in TS.

For instance, on the plane z=0z=0, the form dzdz restricts to zero. Any form containing a factor of dzdz also restricts to zero, such as dx∧dzdx\wedge dz.

Common mistakes

Confusing restriction with substituting coordinates only

For a one-form, replacing zz by 00 in its coefficient functions is not enough. You must also replace the differentials according to the parametrization. On z=0z=0, dzdz becomes zero, while dxdx and dydy remain tangent differentials.

Treating ambient vectors as arbitrary

The restricted form is evaluated only on vectors in TpST_pS. A vector normal to the submanifold is not an allowed input when evaluating a form on SS.

Forgetting the degree bound

If dim⁡S=r\dim S=r, every kk-form on SS with k>rk>r is zero. This follows because an alternating kk-linear map on an rr-dimensional vector space vanishes when k>rk>r.

Assuming every ambient form is uniquely determined by its restriction

Different ambient forms can have the same restriction. On the plane z=0z=0, both dxdx and dx+z dy+dzdx+z\,dy+dz restrict to dxdx, since z=0z=0 and dz=0dz=0 along tangent directions. Restriction loses information in normal directions.

Integration over submanifolds

Integration is defined using the same pullback. If SS is an oriented rr-dimensional submanifold and ω\omega is an rr-form on MM, then in a parametrized region ϕ:U→S\phi:U\to S,

∫Sω=∫Uϕ∗ω,\int_S\omega=\int_U\phi^*\omega,

with the appropriate orientation and a sum over parametrization patches when necessary. This is why pullback is the central operation for integrating ambient differential forms over curves, surfaces, and higher-dimensional submanifolds.

References

  1. Introduction to Smooth Manifolds, John M. Lee
  2. Calculus on Manifolds, Michael Spivak

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