Coulomb's law and electric field intensity

The electric field from any single line charge always points directly away from the line charge, is proportional to the linear charge density, and falls off like $\frac{1}{r}$

In your problem, at any point of interest, you will have an electric field vector that has a component on the y-z plane from the line charge on the x axis, and a component on the x-z plane from the line charge on the y axis.

The total magnitude will be $E=\sqrt{E_{yz}^2 + E_{xz}^2}$

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DONGHUN

Updated on October 21, 2022