Calculate acceleration and time given initial speed, final speed, and travelling distance?
14,182
For constant acceleration, you have two equations that you need to solve for time $t$ and acceleration $a$.
$$x=\frac12at^2$$ $$v=at$$
It is up to you from here.
$$402\ \mathrm m=\frac12at^2$$ $$\left(190\ \mathrm{\frac{km}h}\right)\left(\frac{1000\ \mathrm{\frac m{km}}}{3600\ \mathrm{\frac sh}}\right)=\left(52.777\ \mathrm{\frac ms}\right)at$$
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Author by
pilau
Updated on June 16, 2022Comments
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pilau about 22 hours
A motorcycle is known to accelerate from rest to 190km/h in 402m.
Considering the rate of acceleration is constant, how should I go about calculating the acceleration rate and the time it took the bike to complete the distance?
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aries0152 over 9 yearsTry v=u+at for acceleration.
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pilau over 9 yearsBut I don't know how long it took the bike to cover the stretch. I only know Vi (0), Vf (190km/h), and d (402m).
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Alan Rominger over 9 yearsYou are correct that you need more than just that equation. The other kinematic equation you might want to use is $x=1/2 a t^2$, which uses the fact that you started from rest and had a constant acceleration. I'd advise reading a basic kinematics tutorial online.
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pilau over 9 yearsI advise reading ja72's answer below ;)
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