Why is the enthalpy of vaporization greater than the enthalpy of fusion?

19,239

Enthalpies of phase changes are fundamentally connected to the electrostatic potential energies between molecules. The first thing you need to know is:

There is an attractive force between all molecules at long(ish) distances, and a repelling force at short distances.

If you make a graph of potential energy vs. distance between two molecules, it will look something like this:

Potential energy between two particles

Here the y-axis represents electrostatic potential energy, the x-axis is radial separation (distance between the centers), and the spheres are "molecules."

Since this is a potential energy curve, you can imagine the system as if it were the surface of the earth, and gravity was the potential. In other words, the white molecule "wants" to roll down the valley until it sits next to the gray molecule. If it were any closer than just touching, it would have to climb up another very steep hill. If you try to pull them away, again you have to climb a hill (although it isn't as tall or steep). The result is that unless there is enough kinetic energy for the molecules to move apart, they tend to stick together.

Now, the potential energy function between any two types of molecules will be different, but it will always have the same basic shape. What will change is the "steepness," width, and depth of the valley (or "potential energy well"), and the slope of the infinitely long "hill" to the right of the well.

Since we are talking about relative enthalpies of fusion and vaporization for a given system, we don't have to worry about how this changes for different molecules. We just have to think about what it means to vaporize or melt something, in the context of the spatial separation or relativity of molecules, and how that relates to the shape of this surface.

First let's think about what happens when you add heat to a system of molecules (positive enthalpy change). Heat is a transfer of thermal energy between a hot substance and a cold one. It is defined by a change in temperature, which means that when you add heat to something, its temperature increases (this might be common sense, but in thermodynamics it is important to be very specific). The main thing we need to know about this is:

Temperature is a measure of the average kinetic energy of all molecules in a system

In other words, as the temperature increases, the average kinetic energy (the speed) of the molecules increases.

Let's go back to the potential energy diagram between two molecules. You know that energy is conserved, and so ignoring losses due to friction (there won't be any for molecules) the potential energy that can be gained by a particle is equal to the kinetic energy it started with. In other words, if the particle is at the bottom of the well and has no kinetic energy, it is not going anywhere:

Schematic of potential energy between two particles in a solid

If it literally has no kinetic energy, we are at absolute zero, and this is an ideal crystal (a solid). Real substances in the real world always have some thermal energy, so the molecules are always sort of "wiggling" around at the bottom of their potential energy wells, even in a solid material.

The question is, how much kinetic energy do you need to melt the material?

In a liquid, molecules are free to move but stay close together

This means you need enough energy to let the molecules climb up the well at least a little bit, so that they can slide around each other.

If we draw a "liquid" line approximating how much energy that would take, it might look something like this:

Potential energy between two particles in a liquid

The red line shows the average kinetic energy needed for the particles to pull apart just a little - enough that they can "slide" around each other - but not so much that there is any significant space between them. The height of this line compared to the bottom of the well (times Avogadro's number) is the enthalpy of fusion.

What if we want to vaporize the substance?

In a gas, the molecules are free to move and are very far apart

As the kinetic energy increases, eventually there is enough that the molecules can actually fly apart (their radial separation can approach infinity). That line might look something like this:

Potential Energy for the gas phase

I have drawn the line a little bit shy of the "zero" point - where the average molecule would get to infinite distance - because kinetic energies follow a statistical distribution, which means that some are higher than average, some are lower, and right around this point is where enough molecules would be able to vaporize that we would call it a phase transition. Depending on the particular substance, the line might be higher or lower.

In any case, the height of this line compared to the blue line (times Avogadro's number) is the enthalpy of vaporization.

As you can see, it's a lot higher up. The reason is that for melting, the molecules just need enough energy to "slide" around each other, while for vaporization, they need enough energy to completely escape the well. This means that the enthalpy of vaporization is always going to be higher than the enthalpy of fusion.

Share:
19,239

Related videos on Youtube

ron
Author by

ron

Updated on August 01, 2022

Comments

  • ron
    ron over 1 year

    Why is the molar enthalpy of vaporization of a substance larger than its molar enthalpy of fusion (at constant pressure); for example, in the case of ice and water.

  • A.K.
    A.K. about 5 years
    Welcome to Chemistry.SE! Anyone is welcome to contribute answers but the aim of this site is quality and usefulness to future users (essentially we aren't Yahoo Answers). Please take a minute to look over the help center to better understand our guidelines and question policies.
  • A.K.
    A.K. about 5 years
    You should try to answer why the forces are stronger too otherwise the answer is really incomplete.
  • alexigirl
    alexigirl over 1 year
    Sounds great, but how does it explain the latent heat? Where is the liquid at boiling point on your energy diagram? It seems to have a shallower slope at the right hand end, which would suggest that the heat of vaporisation should be less than the heat of fusion?
  • thomij
    thomij over 1 year
    @alexigirl The red line on the second image represents the liquid at or near the boiling point. The heat of vaporization is the difference between the red and blue lines. The blue line is the liquid at the melting point. The heat of fusion is the difference between the blue line and some line (not pictured) close to the bottom of the well.
  • alexigirl
    alexigirl over 1 year
    If the red line represents the liquid at or near the boiling point, it already has the energy represented by the difference between the red and blue lines. From the graph it would seem that this is enough energy to vaporise the liquid, but we know that this does not happen, we have to keep adding thermal energy for the liquid to vaporise (that would be crazy if once you had heated a pan of water to boiling point it all instantly vaporised). This extra energy is the latent heat of vaporisation. Maybe your red line is too high?
  • thomij
    thomij over 1 year
    @alexigirl I think there still must be some confusion here. Enthalpies of phase change are differences in energy. The enthalpy of vaporization doesn't contain the enthalpy of fusion, it's the energy difference between states where the molecules are mobile but still in close proximity, and the state in which the molecules are completely unbound.
  • alexigirl
    alexigirl over 1 year
    there is definitely still confusion here. You seem to be saying that the red line represents the energy of the liquid state at or near the boiling point, where molecules are mobile but still in close proximity. So the latent heat of vaporisation cannot include the energy difference between the red line and the blue line, because at both these lines the substance is liquid.
  • thomij
    thomij over 1 year
    @alexigirl These diagrams represent the potential energy between a pair of molecules. For a single pair, the energy needed to melt is the difference between zero and the blue line. The energy needed to vaporize is the difference between the red and blue lines. At the boiling point, most of the pairs of atoms will have enough kinetic energy to reach the red line, which gives them enough separation that they can escape the liquid.
  • alexigirl
    alexigirl over 1 year
    So why don't they all escape then? I can heat my kettle to boiling point. But if I then switch it off, most of the water (which was at 100 degrees) does not vaporise.
  • alexigirl
    alexigirl over 1 year
    And if, at the boiling point, the pairs of molecules have enough energy to escape, ie they are already at the red line, why should I include the energy increase between the blue and the red line, which they already possess before they reach the boiling point, in the latent heat of vaporisation? The definition I have learnt of latent heat of vaporisation is the energy required to change the state from liquid to gas at the boiling point.