Trigonometry problem: How far below the surface of the hill is a point $38m$ down the tunnel?
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The horizontal distance from the tunnel entrance at a point $38$m along the tunnel is $h=38\cos(12.25°)$. Then the distance below the tunnel entrance is $v_1=38\sin(12.25°)$ and the corresponding distance of the hillside above that point is $v_2=h\tan(32°)$. The value you want is $v_1+v_2$.
Comments
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HENPAUL 11 months
In the side of a hill that slopes upward at an angle of $32^\circ$, a tunnel is bored sloping downward at an angle of $12^\circ15'$ from the horizontal.
How far below the surface of the hill is a point $38$ meters down the tunnel?
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K Split X almost 7 yearsWhat is " 12º15' from the horizontal"
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The Count almost 7 yearsWhat have you tried? We don't just do random problems without some effort or research on the poster's part.
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Joffan almost 7 yearsThe best advice is probably "Draw a diagram".
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HENPAUL almost 7 yearsThanks but the issue here is that I can't sketch it
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Joffan almost 7 years@HENPAUL added image
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HENPAUL almost 7 yearsVery grateful, I can complete the working
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Jean Marie almost 7 years@HENPAUL For a future question, please, show a little what you have done on the subject.