Is the oxygen molecule $O_2$ fermion or boson?
Solution 1
Regardless of energy state, regardless of the choice of isotope, if we have two identical atoms in this molecule (i.e. same isotope of oxygen), this pair must have even numbers of all nucleons and electrons. This then precludes half-integer total spin, which leads to bosonic properties of the system.
I initially thought a light (photon) can excite the ground state oxygen molecule.
Yes, it can, and this has been done in real experiments, see [1] (PDF available).
However, my colleague said that process is forbidden as fermion and boson hate each other.
This is irrelevant, because simple chemical processes (without ionization) don't change number of fermions, so parity remains the same.
References:
[1]: Steffen Jockusch, Nicholas J. Turro, Elizabeth K. Thompson, Martin Gouterman, James B. Callis, Gamal E. Khalil. Singlet molecular oxygen by direct excitation. Photochem. Photobiol. Sci. 2008, 7 (2) , 235-239. DOI: 10.1039/B714286B.
Solution 2
The rule is simple:
A combination of particles is a fermion is it contains an odd number of fermions otherwise it is boson.
Since $\text{O}_2$ is two of the same particle (assuming both are the same isotope), it is necessarily bosonic.
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Jun-Hyeong Kim
Updated on January 10, 2020Comments
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Jun-Hyeong Kim almost 4 years
I ask something makes me confused.
In generating singlet oxygen molecule, I initially thought a light (photon) can excite the ground state oxygen molecule.
However, my colleague said that process is forbidden as fermion and boson hate each other.
I insisted these are all boson because ground state oxygen molecule has its intrinsic angular momentum of S=1.
I know there must be wrong reasoning in my thought. Otherwise liquid oxygen has to show Bose-Einstein condensation.
Cannot oxygen molecule really absorb a photon to be singlet oxygen molecule?
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my2cts about 4 yearsI see three different questions here, Please use three submissions.
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marshal craft almost 4 yearsDoesn't it simply and definitely depend on the specific case and if the molecules probability distribution respect Pauli exclusion principle or not?
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my2cts about 4 yearsThe assumption of identical nuclei is incorrect for natural oxygen.
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my2cts about 4 yearsOxygen nuclei can have non-zero spin.
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my2cts about 4 yearsThe assumption that both are same isotope is incorrect.
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Ruslan about 4 years@my2cts Given its atomic weight of 15.999 (with $^{16}\mathrm{O}$ abundance of 99.76%), this assumption is pretty reasonable.
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my2cts about 4 yearsWhether it is reasonable depends on what is required.
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Ruslan about 4 years@my2cts well, the OP has mutliple questions in it, so I've answered that part using one of the possibilities as an example. As I elaborated further, this boson/fermion distinction is actually irrelevant here.