How to write equations for a reaction of metals with water


With all technicalities aside, your first equation is on par. The second one should be adjusted a bit for that +2 charge. It is as follows:

$$\ce{Ba(s) + 2HOH(l) -> Ba(OH)2(aq) + H2(g)}$$

NOTE: If need be, you must also take into account the fact that two strong bases are being generated. SO if you wish you might as well dissociate the Barium Hydroxide and the Lithium Hydroxide as well.

Thanks. Correct me if I am wrong.


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Bob Umadbro
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Bob Umadbro

Updated on October 04, 2022


  • Bob Umadbro
    Bob Umadbro 15 days

    Please write two equations for reacting lithium with water and barium with water. Make sure to add the states of matter after each compound.

    Currently, for lithium I have the equation

    $$\ce{2Li(s) + 2H2O(l) -> 2LiOH(aq) + H2(g)}$$

    I have not attempted the second one yet.

    • Asker123
      Asker123 over 7 years
      Considering that $\ce{LiOH}$ is a strong base, the $\ce{Li}$ would become an ion since it is a strong base.
    • Andy
      Andy over 7 years
      I'm pretty sure you are correct. ( You should have confidence and do your homework with confidence. The Barium reaction is very similar and you should be able to do it.
    • Admin
      Admin over 7 years
      Looks fine to me as well, as @Andy says, you should be able to approach the second one (similar to your previous post…) - but keep what Asker123 stated in mind.
  • Andy
    Andy over 7 years
    Wouldn't Hydrogen be produced as a gas as well? A small quantity may remain dissolved but I would think that if any sizable amount of Barium is added, hydrogen gas would be produced since the solubility of hydrogen gas is quite low under standard conditions in water.