How to invert Logic Gate input in Circuitikz

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Using the fresh new circuitikzgit uploaded minutes ago, you can now do this:

\documentclass[border=10pt]{standalone}
\usepackage[siunitx, RPvoltages]{circuitikzgit}
\begin{document}
\begin{circuitikz}
    \draw (0,3) node[american and port] (A)  {P1};
    \node at (A.bin 1) [ocirc, left]{} ;
    \begin{scope}
        \ctikzset{tripoles/american or port/height=1.6}
        \draw (A.out) -- ++(0.5,0) node[american or port,
        number inputs=5, anchor=in 1] (B)  {P2};
        \node at (B.bin 3) [ocirc, left]{} ;
    \end{scope}
    \draw (0,1.5) node[american or port] (C)  {P3};
    \node at (C.bin 2) [ocirc, left]{} ;
    \draw (C.out) |- (B.in 2);
\end{circuitikz}
\end{document}

output from he above snippet

See: https://github.com/circuitikz/circuitikz/issues/166 and https://github.com/circuitikz/circuitikz/pull/168

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Roman Stadler
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Roman Stadler

Updated on August 01, 2022

Comments

  • Roman Stadler
    Roman Stadler over 1 year

    I have drawn the following circuit, but how could the inputs of a Logic Gate be inverted? (As in the scanned picture, but it does not matter which gate exactly, just generally)

    The circuit

    The negated Inputs

    \documentclass[a4paper,12pt]{article}
    
    \usepackage{tikz} %vectorgraphics
    \usetikzlibrary{shapes,arrows,shadows,
    decorations.pathreplacing,backgrounds,calc} 
    %graph/flowchart
    \usepackage[siunitx]{circuitikz}
    
    \begin{document}
    \begin{circuitikz} \draw
    
    (0,0) node[nand port] (nand1) {}
    (3,0) node[nand port] (nand2) {}
    (5,0) node[nand port] (nand3) {}
    
    (3,2) node[nand port] (nand4) {}
    (5,2) node[nand port] (nand5) {}
    
    (3,4) node[nand port] (nand6) {}
    (5,4) node[nand port] (nand7) {}
    
    (0,4) node[nand port] (nand8) {}
    
    (nand1.out) |- (nand2.in 2)
    (nand2.out) -| node[circ,midway]{} (nand3.in 1)
    (nand2.out) -| (nand3.in 2)
    
    (nand8.out) |- (nand6.in 1)
    (nand6.out) -| node[circ,midway]{} (nand7.in 2)
    (nand6.out) -| (nand7.in 1)
    
    (nand4.out) -| node[circ,midway]{} (nand5.in 2)
    (nand4.out) -| (nand5.in 1)
    
    (-2,1) node(B1)[anchor=east] {B}
    (-2,1) -| node[circ,midway]{} (nand1.in 1) 
    to[short,*-] (nand1.in 2)
    (-2,1) -| (nand4.in 2)
    (1,1) node[circ]{} |- (nand6.in 2)
    
    
    (-2,3) node[anchor=east] {A}
    (-2,3) -| node[circ,midway]{} (nand8.in 2) 
    to[short,*-] (nand8.in 1)
    (-2,3) -| (nand4.in 1)
    (0.5,3) node[circ]{} |- (nand2.in 1)
    
    (6,1.97) node[anchor=east] {O2}
    (6,0.0) node[anchor=east] {O3}
    (6,4) node[anchor=east] {O1}
    
    ;\end{circuitikz}
    
    \end{document}
    
    • Rmano
      Rmano over 4 years
      Nice question. I'll look over it tomorrow (it's nighttime here), but I don't think it could be easily done with the current implementation. But seems a valuable enhancement proposal, anyway.
    • Rmano
      Rmano over 4 years
      I am considering it as a enhancement proposal; if you want you can open an issue at github.com/circuitikz/circuitikz/issues
    • Raaja_is_at_topanswers.xyz
      Raaja_is_at_topanswers.xyz over 4 years
      With current circuitikz you cannot achieve this. However, you can use tikz's stock ciruit option to achieve it. Nevertheless, a very useful question though.
  • Raaja_is_at_topanswers.xyz
    Raaja_is_at_topanswers.xyz over 4 years
    when will it be available in CTAN?
  • Rmano
    Rmano over 4 years
    @Raaja I am completing a couple of things more (basically, manual overhaul and fillable shapes) and then I'll do a release. Three to five weeks, if RL doesn't create problems... ;-)
  • Raaja_is_at_topanswers.xyz
    Raaja_is_at_topanswers.xyz over 4 years
    Good to know! Because, it seems many are interested in creating big-logic circuits with ciruittikz (see: tex.stackexchange.com/questions/480034/…). And, I think this is a really nice contribution indeed :).