how to find the gradient using differentiation
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$y'=4x-8$ or, $y'(3)=4(3)-8$ or, $y'(3)=12-8$ or, $y'(3)=4$
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haya
Updated on November 09, 2022Comments
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haya 12 months
I did not understand what do they want from the question, can you help me please?
Find the gradient at the point with $x$-coordinate $3$ on each of the following curves: $y = 2x^2 − 8x + 3$
Thank you.
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Mufasa over 7 yearsHINT: The gradient is defined as the slope of the curve which in turn can be calculated by finding $\frac{dy}{dx}$. You then need to work out the value of $\frac{dy}{dx}$ at the point $x=3$
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