How can I find the value of y given x using matlab / octave
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Yes, let's first find the equation of the line
Notice, the equation of the line passing through the points: $(40, 5)$ & $(50, 1)$ is given as $$y-5=\frac{5-1}{40-50}(x-40)$$ $$y-5=\frac{-2}{5}(x-40)$$ Now, setting $x=42.5$, we get y-coordinate $$y-5=\frac{-2}{5}(42.5-40)$$ $$y=-\frac{2}{5}(2.5)+5$$$$=5-1=4$$ $$\bbox[5px, border:2px solid #C0A000]{\color{red}{y=4}}$$
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Author by
Rick T
Updated on August 07, 2020Comments
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Rick T over 3 years
I have two points on a plot point1=(40,5) and point2=(50,1)
How can I find the value of y given x=42.5 I know y is 4 by looking at the plot but is there away to calculate the y value directly.
I found the slope: y2-y1/x2-x1 (1-5)/(50-40) =-0.4
Example: matlab code:
clf reset pts=[40,5;50,1] %x-y points slope=(pts(2,2)-pts(1,2))/(pts(2,1)-pts(1,1)); %slope plot(pts(:,1),pts(:,2),'-b') %plot line hold on plot(pts(:,1),pts(:,2),'r*') %plot points with stars
PS: I'm using octave 3.8.1 which is like matlab