Finding vertical displacement

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Motion under constant acceleration is given by $\ddot{x}(t) = a.$ Integrating twice gives

$$x(t) = x_0 + v_0t + \frac{at^2}{2}.$$

If you set your initial height to $x_0 = 0$ and assume that $v_0 = 0$ as well then $x(79)$ follows easily.

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Updated on August 01, 2022

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  • user132236
    user132236 over 1 year

    I am being asked to find the distance a shuttle travels upward after a given amount of time. I know that time passed is 79s, the rate of acceleration is 6.244 m/s^2, and the speed at 79s is 493.276 m/s. However I can't figure out what equation to use to find the altitude at that time, 79 s. Please help! Thank you.